3(x-5)+7x=42

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Solution for 3(x-5)+7x=42 equation: 



3(x-5)+7x=42

We move all terms to the left:

3(x-5)+7x-(42)=0

We add all the numbers together, and all the variables

7x+3(x-5)-42=0

We multiply parentheses

7x+3x-15-42=0

We add all the numbers together, and all the variables

10x-57=0

We move all terms containing x to the left, all other terms to the right

10x=57

x=57/10

x=5+7/10

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