3(x-5)+x=4(x-2)-7

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Solution for 3(x-5)+x=4(x-2)-7 equation: 


Simplifying
3(x + -5) + x = 4(x + -2) + -7

Reorder the terms:
3(-5 + x) + x = 4(x + -2) + -7
(-5 * 3 + x * 3) + x = 4(x + -2) + -7
(-15 + 3x) + x = 4(x + -2) + -7

Combine like terms: 3x + x = 4x
-15 + 4x = 4(x + -2) + -7

Reorder the terms:
-15 + 4x = 4(-2 + x) + -7
-15 + 4x = (-2 * 4 + x * 4) + -7
-15 + 4x = (-8 + 4x) + -7

Reorder the terms:
-15 + 4x = -8 + -7 + 4x

Combine like terms: -8 + -7 = -15
-15 + 4x = -15 + 4x

Add '15' to each side of the equation.
-15 + 15 + 4x = -15 + 15 + 4x

Combine like terms: -15 + 15 = 0
0 + 4x = -15 + 15 + 4x
4x = -15 + 15 + 4x

Combine like terms: -15 + 15 = 0
4x = 0 + 4x
4x = 4x

Add '-4x' to each side of the equation.
4x + -4x = 4x + -4x

Combine like terms: 4x + -4x = 0
0 = 4x + -4x

Combine like terms: 4x + -4x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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