3(x-5)-(8+2x)=4(x-7)+2x

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Solution for 3(x-5)-(8+2x)=4(x-7)+2x equation:



3(x-5)-(8+2x)=4(x-7)+2x
We move all terms to the left:
3(x-5)-(8+2x)-(4(x-7)+2x)=0
We add all the numbers together, and all the variables
3(x-5)-(2x+8)-(4(x-7)+2x)=0
We multiply parentheses
3x-(2x+8)-(4(x-7)+2x)-15=0
We get rid of parentheses
3x-2x-(4(x-7)+2x)-8-15=0
We calculate terms in parentheses: -(4(x-7)+2x), so:
4(x-7)+2x
We add all the numbers together, and all the variables
2x+4(x-7)
We multiply parentheses
2x+4x-28
We add all the numbers together, and all the variables
6x-28
Back to the equation:
-(6x-28)
We add all the numbers together, and all the variables
x-(6x-28)-23=0
We get rid of parentheses
x-6x+28-23=0
We add all the numbers together, and all the variables
-5x+5=0
We move all terms containing x to the left, all other terms to the right
-5x=-5
x=-5/-5
x=1

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