3(x-5)-(x+2)=16

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Solution for 3(x-5)-(x+2)=16 equation: 



3(x-5)-(x+2)=16

We move all terms to the left:

3(x-5)-(x+2)-(16)=0

We multiply parentheses

3x-(x+2)-15-16=0

We get rid of parentheses

3x-x-2-15-16=0

We add all the numbers together, and all the variables

2x-33=0

We move all terms containing x to the left, all other terms to the right

2x=33

x=33/2

x=16+1/2

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