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3(x-5)-14=2(x-4)+4
We move all terms to the left:
3(x-5)-14-(2(x-4)+4)=0
We multiply parentheses
3x-(2(x-4)+4)-15-14=0
We calculate terms in parentheses: -(2(x-4)+4), so:We add all the numbers together, and all the variables
2(x-4)+4
We multiply parentheses
2x-8+4
We add all the numbers together, and all the variables
2x-4
Back to the equation:
-(2x-4)
3x-(2x-4)-29=0
We get rid of parentheses
3x-2x+4-29=0
We add all the numbers together, and all the variables
x-25=0
We move all terms containing x to the left, all other terms to the right
x=25
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