3(x-5)-2=-7(-3x+1)-2x

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Solution for 3(x-5)-2=-7(-3x+1)-2x equation: 



3(x-5)-2=-7(-3x+1)-2x

We move all terms to the left:

3(x-5)-2-(-7(-3x+1)-2x)=0

We multiply parentheses

3x-(-7(-3x+1)-2x)-15-2=0



We calculate terms in parentheses: -(-7(-3x+1)-2x), so:

-7(-3x+1)-2x

We add all the numbers together, and all the variables

-2x-7(-3x+1)

We multiply parentheses

-2x+21x-7

We add all the numbers together, and all the variables

19x-7

Back to the equation:

-(19x-7)



We add all the numbers together, and all the variables

3x-(19x-7)-17=0

We get rid of parentheses

3x-19x+7-17=0

We add all the numbers together, and all the variables

-16x-10=0

We move all terms containing x to the left, all other terms to the right

-16x=10

x=10/-16

x=-5/8

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