3(x-5)-4(2x-4)=-2(x+11)

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Solution for 3(x-5)-4(2x-4)=-2(x+11) equation: 



3(x-5)-4(2x-4)=-2(x+11)

We move all terms to the left:

3(x-5)-4(2x-4)-(-2(x+11))=0

We multiply parentheses

3x-8x-(-2(x+11))-15+16=0



We calculate terms in parentheses: -(-2(x+11)), so:

-2(x+11)

We multiply parentheses

-2x-22

Back to the equation:

-(-2x-22)



We add all the numbers together, and all the variables

-5x-(-2x-22)+1=0

We get rid of parentheses

-5x+2x+22+1=0

We add all the numbers together, and all the variables

-3x+23=0

We move all terms containing x to the left, all other terms to the right

-3x=-23

x=-23/-3

x=7+2/3

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