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3(x-5)-4(2x-4)=2(x+11)
We move all terms to the left:
3(x-5)-4(2x-4)-(2(x+11))=0
We multiply parentheses
3x-8x-(2(x+11))-15+16=0
We calculate terms in parentheses: -(2(x+11)), so:We add all the numbers together, and all the variables
2(x+11)
We multiply parentheses
2x+22
Back to the equation:
-(2x+22)
-5x-(2x+22)+1=0
We get rid of parentheses
-5x-2x-22+1=0
We add all the numbers together, and all the variables
-7x-21=0
We move all terms containing x to the left, all other terms to the right
-7x=21
x=21/-7
x=-3
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