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3(x-5)=(2x-5)
We move all terms to the left:
3(x-5)-((2x-5))=0
We multiply parentheses
3x-((2x-5))-15=0
We calculate terms in parentheses: -((2x-5)), so:We get rid of parentheses
(2x-5)
We get rid of parentheses
2x-5
Back to the equation:
-(2x-5)
3x-2x+5-15=0
We add all the numbers together, and all the variables
x-10=0
We move all terms containing x to the left, all other terms to the right
x=10
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