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3(x-5)=(x+5)+x
We move all terms to the left:
3(x-5)-((x+5)+x)=0
We multiply parentheses
3x-((x+5)+x)-15=0
We calculate terms in parentheses: -((x+5)+x), so:We get rid of parentheses
(x+5)+x
We add all the numbers together, and all the variables
x+(x+5)
We get rid of parentheses
x+x+5
We add all the numbers together, and all the variables
2x+5
Back to the equation:
-(2x+5)
3x-2x-5-15=0
We add all the numbers together, and all the variables
x-20=0
We move all terms containing x to the left, all other terms to the right
x=20
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