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3(x-5)=-2(4-x)=
We move all terms to the left:
3(x-5)-(-2(4-x))=0
We add all the numbers together, and all the variables
3(x-5)-(-2(-1x+4))=0
We multiply parentheses
3x-(-2(-1x+4))-15=0
We calculate terms in parentheses: -(-2(-1x+4)), so:We get rid of parentheses
-2(-1x+4)
We multiply parentheses
2x-8
Back to the equation:
-(2x-8)
3x-2x+8-15=0
We add all the numbers together, and all the variables
x-7=0
We move all terms containing x to the left, all other terms to the right
x=7
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