3(x-5)=-3(2x+1)

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Solution for 3(x-5)=-3(2x+1) equation: 



3(x-5)=-3(2x+1)

We move all terms to the left:

3(x-5)-(-3(2x+1))=0

We multiply parentheses

3x-(-3(2x+1))-15=0



We calculate terms in parentheses: -(-3(2x+1)), so:

-3(2x+1)

We multiply parentheses

-6x-3

Back to the equation:

-(-6x-3)



We get rid of parentheses

3x+6x+3-15=0

We add all the numbers together, and all the variables

9x-12=0

We move all terms containing x to the left, all other terms to the right

9x=12

x=12/9

x=1+1/3

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