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3(x-5)=-4(2x-3)
We move all terms to the left:
3(x-5)-(-4(2x-3))=0
We multiply parentheses
3x-(-4(2x-3))-15=0
We calculate terms in parentheses: -(-4(2x-3)), so:We get rid of parentheses
-4(2x-3)
We multiply parentheses
-8x+12
Back to the equation:
-(-8x+12)
3x+8x-12-15=0
We add all the numbers together, and all the variables
11x-27=0
We move all terms containing x to the left, all other terms to the right
11x=27
x=27/11
x=2+5/11
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