3(x-5)=19+-2

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Solution for 3(x-5)=19+-2 equation: 



3(x-5)=19+-2

We move all terms to the left:

3(x-5)-(19+-2)=0

We add all the numbers together, and all the variables

3(x-5)-17=0

We multiply parentheses

3x-15-17=0

We add all the numbers together, and all the variables

3x-32=0

We move all terms containing x to the left, all other terms to the right

3x=32

x=32/3

x=10+2/3

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