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3(x-5)=2(10-x)
We move all terms to the left:
3(x-5)-(2(10-x))=0
We add all the numbers together, and all the variables
3(x-5)-(2(-1x+10))=0
We multiply parentheses
3x-(2(-1x+10))-15=0
We calculate terms in parentheses: -(2(-1x+10)), so:We get rid of parentheses
2(-1x+10)
We multiply parentheses
-2x+20
Back to the equation:
-(-2x+20)
3x+2x-20-15=0
We add all the numbers together, and all the variables
5x-35=0
We move all terms containing x to the left, all other terms to the right
5x=35
x=35/5
x=7
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