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3(x-5)=2(4x+1)
We move all terms to the left:
3(x-5)-(2(4x+1))=0
We multiply parentheses
3x-(2(4x+1))-15=0
We calculate terms in parentheses: -(2(4x+1)), so:We get rid of parentheses
2(4x+1)
We multiply parentheses
8x+2
Back to the equation:
-(8x+2)
3x-8x-2-15=0
We add all the numbers together, and all the variables
-5x-17=0
We move all terms containing x to the left, all other terms to the right
-5x=17
x=17/-5
x=-3+2/5
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