3(x-5)=2(x+2)+3(x-5)

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Solution for 3(x-5)=2(x+2)+3(x-5) equation: 



3(x-5)=2(x+2)+3(x-5)

We move all terms to the left:

3(x-5)-(2(x+2)+3(x-5))=0

We multiply parentheses

3x-(2(x+2)+3(x-5))-15=0



We calculate terms in parentheses: -(2(x+2)+3(x-5)), so:

2(x+2)+3(x-5)

We multiply parentheses

2x+3x+4-15

We add all the numbers together, and all the variables

5x-11

Back to the equation:

-(5x-11)



We get rid of parentheses

3x-5x+11-15=0

We add all the numbers together, and all the variables

-2x-4=0

We move all terms containing x to the left, all other terms to the right

-2x=4

x=4/-2

x=-2

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