3(x-5)=2(x+2)+5x-22

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Solution for 3(x-5)=2(x+2)+5x-22 equation: 



3(x-5)=2(x+2)+5x-22

We move all terms to the left:

3(x-5)-(2(x+2)+5x-22)=0

We multiply parentheses

3x-(2(x+2)+5x-22)-15=0



We calculate terms in parentheses: -(2(x+2)+5x-22), so:

2(x+2)+5x-22

We add all the numbers together, and all the variables

5x+2(x+2)-22

We multiply parentheses

5x+2x+4-22

We add all the numbers together, and all the variables

7x-18

Back to the equation:

-(7x-18)



We get rid of parentheses

3x-7x+18-15=0

We add all the numbers together, and all the variables

-4x+3=0

We move all terms containing x to the left, all other terms to the right

-4x=-3

x=-3/-4

x=3/4

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