3(x-5)=2(x+3)+11

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Solution for 3(x-5)=2(x+3)+11 equation: 



3(x-5)=2(x+3)+11

We move all terms to the left:

3(x-5)-(2(x+3)+11)=0

We multiply parentheses

3x-(2(x+3)+11)-15=0



We calculate terms in parentheses: -(2(x+3)+11), so:

2(x+3)+11

We multiply parentheses

2x+6+11

We add all the numbers together, and all the variables

2x+17

Back to the equation:

-(2x+17)



We get rid of parentheses

3x-2x-17-15=0

We add all the numbers together, and all the variables

x-32=0

We move all terms containing x to the left, all other terms to the right

x=32

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