3(x-5)=2(x+4)+1

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Solution for 3(x-5)=2(x+4)+1 equation: 



3(x-5)=2(x+4)+1

We move all terms to the left:

3(x-5)-(2(x+4)+1)=0

We multiply parentheses

3x-(2(x+4)+1)-15=0



We calculate terms in parentheses: -(2(x+4)+1), so:

2(x+4)+1

We multiply parentheses

2x+8+1

We add all the numbers together, and all the variables

2x+9

Back to the equation:

-(2x+9)



We get rid of parentheses

3x-2x-9-15=0

We add all the numbers together, and all the variables

x-24=0

We move all terms containing x to the left, all other terms to the right

x=24

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