3(x-5)=2(x-5)+

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Solution for 3(x-5)=2(x-5)+ equation: 



3(x-5)=2(x-5)+

We move all terms to the left:

3(x-5)-(2(x-5)+)=0

We multiply parentheses

3x-(2(x-5)+)-15=0



We calculate terms in parentheses: -(2(x-5)+), so:

2(x-5)+

We add all the numbers together, and all the variables

2(x-5)

We multiply parentheses

2x-10

Back to the equation:

-(2x-10)



We get rid of parentheses

3x-2x+10-15=0

We add all the numbers together, and all the variables

x-5=0

We move all terms containing x to the left, all other terms to the right

x=5

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