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3(x-5)=3(2x-1)
We move all terms to the left:
3(x-5)-(3(2x-1))=0
We multiply parentheses
3x-(3(2x-1))-15=0
We calculate terms in parentheses: -(3(2x-1)), so:We get rid of parentheses
3(2x-1)
We multiply parentheses
6x-3
Back to the equation:
-(6x-3)
3x-6x+3-15=0
We add all the numbers together, and all the variables
-3x-12=0
We move all terms containing x to the left, all other terms to the right
-3x=12
x=12/-3
x=-4
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