3(x-5)=40+1x

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Solution for 3(x-5)=40+1x equation: 



3(x-5)=40+1x

We move all terms to the left:

3(x-5)-(40+1x)=0

We add all the numbers together, and all the variables

3(x-5)-(x+40)=0

We multiply parentheses

3x-(x+40)-15=0

We get rid of parentheses

3x-x-40-15=0

We add all the numbers together, and all the variables

2x-55=0

We move all terms containing x to the left, all other terms to the right

2x=55

x=55/2

x=27+1/2

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