3(x-5)=40+1xX=

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Solution for 3(x-5)=40+1xX= equation: 



3(x-5)=40+1xx=

We move all terms to the left:

3(x-5)-(40+1xx)=0

We add all the numbers together, and all the variables

3(x-5)-(1xx+40)=0

We multiply parentheses

3x-(1xx+40)-15=0

We get rid of parentheses

3x-1xx-40-15=0

We add all the numbers together, and all the variables

3x-1xx-55=0

We move all terms containing x to the left, all other terms to the right

3x-1xx=55

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