3(x-5)=4x-2(x+3)

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Solution for 3(x-5)=4x-2(x+3) equation: 



3(x-5)=4x-2(x+3)

We move all terms to the left:

3(x-5)-(4x-2(x+3))=0

We multiply parentheses

3x-(4x-2(x+3))-15=0



We calculate terms in parentheses: -(4x-2(x+3)), so:

4x-2(x+3)

We multiply parentheses

4x-2x-6

We add all the numbers together, and all the variables

2x-6

Back to the equation:

-(2x-6)



We get rid of parentheses

3x-2x+6-15=0

We add all the numbers together, and all the variables

x-9=0

We move all terms containing x to the left, all other terms to the right

x=9

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