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3(x-5)=5(2x+3)+26
We move all terms to the left:
3(x-5)-(5(2x+3)+26)=0
We multiply parentheses
3x-(5(2x+3)+26)-15=0
We calculate terms in parentheses: -(5(2x+3)+26), so:We get rid of parentheses
5(2x+3)+26
We multiply parentheses
10x+15+26
We add all the numbers together, and all the variables
10x+41
Back to the equation:
-(10x+41)
3x-10x-41-15=0
We add all the numbers together, and all the variables
-7x-56=0
We move all terms containing x to the left, all other terms to the right
-7x=56
x=56/-7
x=-8
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