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3(x-5)=5(2x-6)+3
We move all terms to the left:
3(x-5)-(5(2x-6)+3)=0
We multiply parentheses
3x-(5(2x-6)+3)-15=0
We calculate terms in parentheses: -(5(2x-6)+3), so:We get rid of parentheses
5(2x-6)+3
We multiply parentheses
10x-30+3
We add all the numbers together, and all the variables
10x-27
Back to the equation:
-(10x-27)
3x-10x+27-15=0
We add all the numbers together, and all the variables
-7x+12=0
We move all terms containing x to the left, all other terms to the right
-7x=-12
x=-12/-7
x=1+5/7
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