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3(x-5)=5(x+1)
We move all terms to the left:
3(x-5)-(5(x+1))=0
We multiply parentheses
3x-(5(x+1))-15=0
We calculate terms in parentheses: -(5(x+1)), so:We get rid of parentheses
5(x+1)
We multiply parentheses
5x+5
Back to the equation:
-(5x+5)
3x-5x-5-15=0
We add all the numbers together, and all the variables
-2x-20=0
We move all terms containing x to the left, all other terms to the right
-2x=20
x=20/-2
x=-10
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