3(x-5)=6(x+5)-18

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Solution for 3(x-5)=6(x+5)-18 equation: 



3(x-5)=6(x+5)-18

We move all terms to the left:

3(x-5)-(6(x+5)-18)=0

We multiply parentheses

3x-(6(x+5)-18)-15=0



We calculate terms in parentheses: -(6(x+5)-18), so:

6(x+5)-18

We multiply parentheses

6x+30-18

We add all the numbers together, and all the variables

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

3x-6x-12-15=0

We add all the numbers together, and all the variables

-3x-27=0

We move all terms containing x to the left, all other terms to the right

-3x=27

x=27/-3

x=-9

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