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3(x-5)=6(x+6)
We move all terms to the left:
3(x-5)-(6(x+6))=0
We multiply parentheses
3x-(6(x+6))-15=0
We calculate terms in parentheses: -(6(x+6)), so:We get rid of parentheses
6(x+6)
We multiply parentheses
6x+36
Back to the equation:
-(6x+36)
3x-6x-36-15=0
We add all the numbers together, and all the variables
-3x-51=0
We move all terms containing x to the left, all other terms to the right
-3x=51
x=51/-3
x=-17
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