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3(x-5)=6+2(x-3)
We move all terms to the left:
3(x-5)-(6+2(x-3))=0
We multiply parentheses
3x-(6+2(x-3))-15=0
We calculate terms in parentheses: -(6+2(x-3)), so:We add all the numbers together, and all the variables
6+2(x-3)
determiningTheFunctionDomain 2(x-3)+6
We multiply parentheses
2x-6+6
We add all the numbers together, and all the variables
2x
Back to the equation:
-(2x)
x-15=0
We move all terms containing x to the left, all other terms to the right
x=15
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