3(x-5)=x+2(x+1)

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Solution for 3(x-5)=x+2(x+1) equation: 



3(x-5)=x+2(x+1)

We move all terms to the left:

3(x-5)-(x+2(x+1))=0

We multiply parentheses

3x-(x+2(x+1))-15=0



We calculate terms in parentheses: -(x+2(x+1)), so:

x+2(x+1)

We multiply parentheses

x+2x+2

We add all the numbers together, and all the variables

3x+2

Back to the equation:

-(3x+2)



We get rid of parentheses

3x-3x-2-15=0

We add all the numbers together, and all the variables

-17!=0

There is no solution for this equation

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