If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3(x-5+2(x-3+4)-5-2x)-3(2-x+4(3-x-2)+5-2x)=1
We move all terms to the left:
3(x-5+2(x-3+4)-5-2x)-3(2-x+4(3-x-2)+5-2x)-(1)=0
We add all the numbers together, and all the variables
3(x-5+2(x+1)-5-2x)-3(2-x+4(-1x+1)+5-2x)-1=0
We move all terms containing x to the left, all other terms to the right
3(x-5+2(x+1)-5-2x)-3(2-x+4(-1x+1)+5-2x)=1
| 3-4x-x=1-4x | | 6x+29+3x+124=90 | | 15/20=9x | | 4x+6x=4x+6 | | x+10+x+10=3x+14 | | X³-6x²+8=0 | | -3/5+w=1/4 | | 2=14-4n | | 3=1g-10 | | 4(y-7)=-4 | | 2(x/2)-4=(-9)2 | | 14=d/3+ 12 | | 22=1v+11 | | 14=d3+ 12 | | 27=2p-5 | | 9=21-4r | | -2(4x-8)+3x=2x+11 | | 5=1n-3 | | 2/9-x/2=3 | | 0=-5r-7r | | 2/9-x/2=3/1 | | 3z-5=-2z+2 | | 6x+3-18x=39 | | 11=10d-9 | | 6=1g-3 | | 3x-17=-7 | | 14=1-2n-1 | | 33=1j+20 | | 1/2m-1=8 | | 36=9q | | 4x=28=92 | | 4.8=8w-7.6 |