3(x-6)(x-2)=96

Solution for 3(x-6)(x-2)=96 equation:

3(x-6)(x-2)=96

We move all terms to the left:

3(x-6)(x-2)-(96)=0

We multiply parentheses ..

3(+x^2-2x-6x+12)-96=0

We multiply parentheses

3x^2-6x-18x+36-96=0

We add all the numbers together, and all the variables

3x^2-24x-60=0

a = 3; b = -24; c = -60;
Δ = b2-4ac
Δ = -242-4·3·(-60)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-36}{2*3}=\frac{-12}{6}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+36}{2*3}=\frac{60}{6}
=10
$