3(x-6)+12=6(x+1)-3

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Solution for 3(x-6)+12=6(x+1)-3 equation: 



3(x-6)+12=6(x+1)-3

We move all terms to the left:

3(x-6)+12-(6(x+1)-3)=0

We multiply parentheses

3x-(6(x+1)-3)-18+12=0



We calculate terms in parentheses: -(6(x+1)-3), so:

6(x+1)-3

We multiply parentheses

6x+6-3

We add all the numbers together, and all the variables

6x+3

Back to the equation:

-(6x+3)



We add all the numbers together, and all the variables

3x-(6x+3)-6=0

We get rid of parentheses

3x-6x-3-6=0

We add all the numbers together, and all the variables

-3x-9=0

We move all terms containing x to the left, all other terms to the right

-3x=9

x=9/-3

x=-3

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