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3(x-6)+1=x+2(x-3)
We move all terms to the left:
3(x-6)+1-(x+2(x-3))=0
We multiply parentheses
3x-(x+2(x-3))-18+1=0
We calculate terms in parentheses: -(x+2(x-3)), so:We add all the numbers together, and all the variables
x+2(x-3)
We multiply parentheses
x+2x-6
We add all the numbers together, and all the variables
3x-6
Back to the equation:
-(3x-6)
3x-(3x-6)-17=0
We get rid of parentheses
3x-3x+6-17=0
We add all the numbers together, and all the variables
-11!=0
There is no solution for this equation
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