3(x-6)+24=50+4(x+10)

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Solution for 3(x-6)+24=50+4(x+10) equation: 



3(x-6)+24=50+4(x+10)

We move all terms to the left:

3(x-6)+24-(50+4(x+10))=0

We multiply parentheses

3x-(50+4(x+10))-18+24=0



We calculate terms in parentheses: -(50+4(x+10)), so:

50+4(x+10)

determiningTheFunctionDomain
4(x+10)+50

We multiply parentheses

4x+40+50

We add all the numbers together, and all the variables

4x+90

Back to the equation:

-(4x+90)



We add all the numbers together, and all the variables

3x-(4x+90)+6=0

We get rid of parentheses

3x-4x-90+6=0

We add all the numbers together, and all the variables

-1x-84=0

We move all terms containing x to the left, all other terms to the right

-x=84

x=84/-1

x=-84

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