3(x-6)+4x=50-5(2x+1)

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Solution for 3(x-6)+4x=50-5(2x+1) equation: 



3(x-6)+4x=50-5(2x+1)

We move all terms to the left:

3(x-6)+4x-(50-5(2x+1))=0

We add all the numbers together, and all the variables

4x+3(x-6)-(50-5(2x+1))=0

We multiply parentheses

4x+3x-(50-5(2x+1))-18=0



We calculate terms in parentheses: -(50-5(2x+1)), so:

50-5(2x+1)

determiningTheFunctionDomain
-5(2x+1)+50

We multiply parentheses

-10x-5+50

We add all the numbers together, and all the variables

-10x+45

Back to the equation:

-(-10x+45)



We add all the numbers together, and all the variables

7x-(-10x+45)-18=0

We get rid of parentheses

7x+10x-45-18=0

We add all the numbers together, and all the variables

17x-63=0

We move all terms containing x to the left, all other terms to the right

17x=63

x=63/17

x=3+12/17

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