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3(x-6)+5x=6x-2(x-5)
We move all terms to the left:
3(x-6)+5x-(6x-2(x-5))=0
We add all the numbers together, and all the variables
5x+3(x-6)-(6x-2(x-5))=0
We multiply parentheses
5x+3x-(6x-2(x-5))-18=0
We calculate terms in parentheses: -(6x-2(x-5)), so:We add all the numbers together, and all the variables
6x-2(x-5)
We multiply parentheses
6x-2x+10
We add all the numbers together, and all the variables
4x+10
Back to the equation:
-(4x+10)
8x-(4x+10)-18=0
We get rid of parentheses
8x-4x-10-18=0
We add all the numbers together, and all the variables
4x-28=0
We move all terms containing x to the left, all other terms to the right
4x=28
x=28/4
x=7
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