3(x-6)-2(x-4)=2x-7-3(2+x)

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Solution for 3(x-6)-2(x-4)=2x-7-3(2+x) equation: 



3(x-6)-2(x-4)=2x-7-3(2+x)

We move all terms to the left:

3(x-6)-2(x-4)-(2x-7-3(2+x))=0

We add all the numbers together, and all the variables

3(x-6)-2(x-4)-(2x-7-3(x+2))=0

We multiply parentheses

3x-2x-(2x-7-3(x+2))-18+8=0



We calculate terms in parentheses: -(2x-7-3(x+2)), so:

2x-7-3(x+2)

determiningTheFunctionDomain
2x-3(x+2)-7

We multiply parentheses

2x-3x-6-7

We add all the numbers together, and all the variables

-1x-13

Back to the equation:

-(-1x-13)



We add all the numbers together, and all the variables

x-(-1x-13)-10=0

We get rid of parentheses

x+1x+13-10=0

We add all the numbers together, and all the variables

2x+3=0

We move all terms containing x to the left, all other terms to the right

2x=-3

x=-3/2

x=-1+1/2

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