3(x-6)-2(x-4)=2x-7-3(2+x)

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Solution for 3(x-6)-2(x-4)=2x-7-3(2+x) equation:



3(x-6)-2(x-4)=2x-7-3(2+x)
We move all terms to the left:
3(x-6)-2(x-4)-(2x-7-3(2+x))=0
We add all the numbers together, and all the variables
3(x-6)-2(x-4)-(2x-7-3(x+2))=0
We multiply parentheses
3x-2x-(2x-7-3(x+2))-18+8=0
We calculate terms in parentheses: -(2x-7-3(x+2)), so:
2x-7-3(x+2)
determiningTheFunctionDomain 2x-3(x+2)-7
We multiply parentheses
2x-3x-6-7
We add all the numbers together, and all the variables
-1x-13
Back to the equation:
-(-1x-13)
We add all the numbers together, and all the variables
x-(-1x-13)-10=0
We get rid of parentheses
x+1x+13-10=0
We add all the numbers together, and all the variables
2x+3=0
We move all terms containing x to the left, all other terms to the right
2x=-3
x=-3/2
x=-1+1/2

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