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3(x-6)-8x=-+5(2x+1)
We move all terms to the left:
3(x-6)-8x-(-+5(2x+1))=0
We add all the numbers together, and all the variables
-8x+3(x-6)-(-+5(2x+1))=0
We use the square of the difference formula
-8x+3(x-6)-(-5(2x+1))=0
We multiply parentheses
-8x+3x-(-5(2x+1))-18=0
We calculate terms in parentheses: -(-5(2x+1)), so:We add all the numbers together, and all the variables
-5(2x+1)
We multiply parentheses
-10x-5
Back to the equation:
-(-10x-5)
-5x-(-10x-5)-18=0
We get rid of parentheses
-5x+10x+5-18=0
We add all the numbers together, and all the variables
5x-13=0
We move all terms containing x to the left, all other terms to the right
5x=13
x=13/5
x=2+3/5
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