3(x-6)=2(x+3)+6

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Solution for 3(x-6)=2(x+3)+6 equation: 



3(x-6)=2(x+3)+6

We move all terms to the left:

3(x-6)-(2(x+3)+6)=0

We multiply parentheses

3x-(2(x+3)+6)-18=0



We calculate terms in parentheses: -(2(x+3)+6), so:

2(x+3)+6

We multiply parentheses

2x+6+6

We add all the numbers together, and all the variables

2x+12

Back to the equation:

-(2x+12)



We get rid of parentheses

3x-2x-12-18=0

We add all the numbers together, and all the variables

x-30=0

We move all terms containing x to the left, all other terms to the right

x=30

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