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3(x-6)x=10
We move all terms to the left:
3(x-6)x-(10)=0
We multiply parentheses
3x^2-18x-10=0
a = 3; b = -18; c = -10;
Δ = b2-4ac
Δ = -182-4·3·(-10)
Δ = 444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{444}=\sqrt{4*111}=\sqrt{4}*\sqrt{111}=2\sqrt{111}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{111}}{2*3}=\frac{18-2\sqrt{111}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{111}}{2*3}=\frac{18+2\sqrt{111}}{6} $
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