3(x-7)+(x-4)=15

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Solution for 3(x-7)+(x-4)=15 equation: 



3(x-7)+(x-4)=15

We move all terms to the left:

3(x-7)+(x-4)-(15)=0

We multiply parentheses

3x+(x-4)-21-15=0

We get rid of parentheses

3x+x-4-21-15=0

We add all the numbers together, and all the variables

4x-40=0

We move all terms containing x to the left, all other terms to the right

4x=40

x=40/4

x=10

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