3(x-7)+20=12+2(x+3)

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Solution for 3(x-7)+20=12+2(x+3) equation: 



3(x-7)+20=12+2(x+3)

We move all terms to the left:

3(x-7)+20-(12+2(x+3))=0

We multiply parentheses

3x-(12+2(x+3))-21+20=0



We calculate terms in parentheses: -(12+2(x+3)), so:

12+2(x+3)

determiningTheFunctionDomain
2(x+3)+12

We multiply parentheses

2x+6+12

We add all the numbers together, and all the variables

2x+18

Back to the equation:

-(2x+18)



We add all the numbers together, and all the variables

3x-(2x+18)-1=0

We get rid of parentheses

3x-2x-18-1=0

We add all the numbers together, and all the variables

x-19=0

We move all terms containing x to the left, all other terms to the right

x=19

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