3(x-7)+2x=-3(x-4)+11

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Solution for 3(x-7)+2x=-3(x-4)+11 equation: 



3(x-7)+2x=-3(x-4)+11

We move all terms to the left:

3(x-7)+2x-(-3(x-4)+11)=0

We add all the numbers together, and all the variables

2x+3(x-7)-(-3(x-4)+11)=0

We multiply parentheses

2x+3x-(-3(x-4)+11)-21=0



We calculate terms in parentheses: -(-3(x-4)+11), so:

-3(x-4)+11

We multiply parentheses

-3x+12+11

We add all the numbers together, and all the variables

-3x+23

Back to the equation:

-(-3x+23)



We add all the numbers together, and all the variables

5x-(-3x+23)-21=0

We get rid of parentheses

5x+3x-23-21=0

We add all the numbers together, and all the variables

8x-44=0

We move all terms containing x to the left, all other terms to the right

8x=44

x=44/8

x=5+1/2

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