3(x-7)+8=4(1-x)-2(x+10)

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Solution for 3(x-7)+8=4(1-x)-2(x+10) equation: 



3(x-7)+8=4(1-x)-2(x+10)

We move all terms to the left:

3(x-7)+8-(4(1-x)-2(x+10))=0

We add all the numbers together, and all the variables

3(x-7)-(4(-1x+1)-2(x+10))+8=0

We multiply parentheses

3x-(4(-1x+1)-2(x+10))-21+8=0



We calculate terms in parentheses: -(4(-1x+1)-2(x+10)), so:

4(-1x+1)-2(x+10)

We multiply parentheses

-4x-2x+4-20

We add all the numbers together, and all the variables

-6x-16

Back to the equation:

-(-6x-16)



We add all the numbers together, and all the variables

3x-(-6x-16)-13=0

We get rid of parentheses

3x+6x+16-13=0

We add all the numbers together, and all the variables

9x+3=0

We move all terms containing x to the left, all other terms to the right

9x=-3

x=-3/9

x=-1/3

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