3(x-7)+8=4(1-x)-2(x+10)

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Solution for 3(x-7)+8=4(1-x)-2(x+10) equation:



3(x-7)+8=4(1-x)-2(x+10)
We move all terms to the left:
3(x-7)+8-(4(1-x)-2(x+10))=0
We add all the numbers together, and all the variables
3(x-7)-(4(-1x+1)-2(x+10))+8=0
We multiply parentheses
3x-(4(-1x+1)-2(x+10))-21+8=0
We calculate terms in parentheses: -(4(-1x+1)-2(x+10)), so:
4(-1x+1)-2(x+10)
We multiply parentheses
-4x-2x+4-20
We add all the numbers together, and all the variables
-6x-16
Back to the equation:
-(-6x-16)
We add all the numbers together, and all the variables
3x-(-6x-16)-13=0
We get rid of parentheses
3x+6x+16-13=0
We add all the numbers together, and all the variables
9x+3=0
We move all terms containing x to the left, all other terms to the right
9x=-3
x=-3/9
x=-1/3

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