3(x-7)+8x=19+3x

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Solution for 3(x-7)+8x=19+3x equation:



3(x-7)+8x=19+3x
We move all terms to the left:
3(x-7)+8x-(19+3x)=0
We add all the numbers together, and all the variables
3(x-7)+8x-(3x+19)=0
We add all the numbers together, and all the variables
8x+3(x-7)-(3x+19)=0
We multiply parentheses
8x+3x-(3x+19)-21=0
We get rid of parentheses
8x+3x-3x-19-21=0
We add all the numbers together, and all the variables
8x-40=0
We move all terms containing x to the left, all other terms to the right
8x=40
x=40/8
x=5

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