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3(x-7)=2(x+3)
We move all terms to the left:
3(x-7)-(2(x+3))=0
We multiply parentheses
3x-(2(x+3))-21=0
We calculate terms in parentheses: -(2(x+3)), so:We get rid of parentheses
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
3x-2x-6-21=0
We add all the numbers together, and all the variables
x-27=0
We move all terms containing x to the left, all other terms to the right
x=27
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