3(x-7)=7(x-3)+4

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Solution for 3(x-7)=7(x-3)+4 equation: 



3(x-7)=7(x-3)+4

We move all terms to the left:

3(x-7)-(7(x-3)+4)=0

We multiply parentheses

3x-(7(x-3)+4)-21=0



We calculate terms in parentheses: -(7(x-3)+4), so:

7(x-3)+4

We multiply parentheses

7x-21+4

We add all the numbers together, and all the variables

7x-17

Back to the equation:

-(7x-17)



We get rid of parentheses

3x-7x+17-21=0

We add all the numbers together, and all the variables

-4x-4=0

We move all terms containing x to the left, all other terms to the right

-4x=4

x=4/-4

x=-1

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